Loading Please Wait...

Logo Lynxsia IT Solutions

JavaScript Ajax XMLHttpRequest Send

JS Ajax Request

The XMLHttpRequest object is used to request data from a server.

Send a Request To a Server

To send a request to a server, we use the open() and send() methods of the XMLHttpRequest object.

					 
        
          xhttp.open("GET", "ajax_info.txt", true);
          xhttp.send();
        
      
Method Description
open(method, url, async) Specifies the type of request
method: the type of request: GET or POST
url: the server (file) location
async: true (asynchronous) or false (synchronous)
send() Sends the request to the server (used for GET)
send(string) Sends the request to the server (used for POST)
The url - A File On a Server

The url parameter of the open() method, is an address to a file on a server.

The file can be any kind of file, like .txt and .xml, or server scripting files like .asp and .php (which can perform actions on the server before sending the response back).

					 
        
          xhttp.open("GET", "ajax_test.php");
        
      
Asynchronous Request

Server requests should be sent asynchronously.

The async parameter of the open() method should be set to true.

By sending asynchronously, the JavaScript does not have to wait for the server response, but can instead:

  • execute other scripts while waiting for server response
  • deal with the response after the response is ready
					 
        
          xhttp.open("GET", "ajax_test.php", true);
        
      

The default value for the async parameter is async = true.

You can safely remove the third parameter from your code.

GET or POST?

GET is simpler and faster than POST, and can be used in most cases.

However, always use POST requests when:

  • A cached file is not an option (update a file or database on the server).
  • Sending a large amount of data to the server (POST has no size limitations).
  • Sending user input (which can contain unknown characters), POST is more robust and secure than GET.
GET Requests

A simple GET request:

					 
        
          xhttp.open("GET", "demo_get.php");
          xhttp.send();
        
      

In the example above, you may get a cached result. To avoid this, add a unique ID to the URL:

					 
        
          xhttp.open("GET", "demo_get.php?id=" + Math.random());
          xhttp.send();
        
      

If you want to send information (parameter) with the GET method, add the information to the URL:

					 
        
          xhttp.open("GET", "demo_get2.php?name='Lynxsia IT Solutions'&email=info@lynxsia.com");
          xhttp.send();
        
      
POST Requests

A simple POST request:

					 
        
          xhttp.open("POST", "demo_post.php");
          xhttp.send();
        
      

To POST data like an HTML form, add an HTTP header with setRequestHeader(). Specify the data you want to send in the send() method:

The setRequestHeader(header, value) adds HTTP headers to the request.

					 
        
          xhttp.open("POST", "ajax_test.php");
          xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
          xhttp.send("name='Lynxsia IT Solutions'&email=info@lynxsia.com");
        
      
Synchronous Request

To execute a synchronous request, change the third parameter in the open() method to false:

					 
        
          xhttp.open("GET", "ajax_info.txt", false);
        
      

Sometimes async = false are used for quick testing. You will also find synchronous requests in older JavaScript code.

Since the code will wait for server completion, there is no need for an onreadystatechange function:

					 
        
          xhttp.open("GET", "ajax_info.txt", false);
          xhttp.send();
          alert(xhttp.responseText);
        
      

Synchronous XMLHttpRequest (async = false) is not recommended because the JavaScript will stop executing until the server response is ready. If the server is busy or slow, the application will hang or stop.

Modern developer tools are encouraged to warn about using synchronous requests and may throw an InvalidAccessError exception when it occurs.

How you feel about this blog:

Share this blog on:

Report Us

If you find any error in the turtorials, or want to share your suggestion/feedback, feel free to send us email at: info@lynxsia.com

Contact Us
Ads
Logo
Lynxsia IT Solutions

We are concern with various development process like website design & development, E-commerce development, Software development, Application development, SMS & Bulk SMS Provider, PWA Development, and many more..

Kotwali Road, Chhiptehri, Banda, 210001, UP, India

Copyright © 2022, Lynxsia IT Solutions, All rights reserved